Plzz answer quick...... free 50 points. ... ans. no. 3
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rosyy1:
it is of 5 pts
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Let the first zero be "a"
and second zero be "-a"
sum of zeroes = -b/a
a + (-a) = (8k²-40k)/4
a - a = 2k²-10k
0 = 2k²-10k
0 = 2k (k -5)
2k = 0 , k - 5 = 0
k = 0,. K = 5
hence, k = 5,0
and second zero be "-a"
sum of zeroes = -b/a
a + (-a) = (8k²-40k)/4
a - a = 2k²-10k
0 = 2k²-10k
0 = 2k (k -5)
2k = 0 , k - 5 = 0
k = 0,. K = 5
hence, k = 5,0
Answered by
0
Answer:
Let the first zero be "a"
and second zero be "-a"
sum of zeroes = -b/a
a + (-a) = (8k²-40k)/4
a - a = 2k²-10k
0 = 2k²-10k
0 = 2k (k -5)
2k = 0 , k - 5 = 0
k = 0,. K = 5
hence, k = 5,0
Step-by-step explanation:
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