Question

Plzz answer quickly... ​

Answer 1

${\bold{\green{\huge{Your\:Answer}}}}$

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Option

(3) $\frac{1}{a}ln\frac{(aL+b)}{b}$

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step-by-step explanation:

First of all,

let,

ax + b = t

on differentiation of both sides wrt x,

we get,

=> adx = dt

=> dx = dt/a

Now,

putting this value in the question,

and transforming,

we get,

integrated part in the form of ln a

further,

putting the limiting value,

and,

simplifying the logarithmic terms,

we get,

the result as

$\frac{1}{a}ln\frac{(aL+b)}{b}$

Hence,

Option (3) is correct.

Note :-

see the aboce attachment.