Question

plzz answer these 2 questions.....

Answer 1

Hey
here is your answer........

$= \frac{2}{5} \times \frac{ - 10}{3} \\ = \frac{ - 4}{3} \\ reciprocal \: of \: \frac{ - 4}{3} = \frac{ - 3}{4} \\ \\ ( \frac{1}{2} - \frac{1}{3} ) = \frac{3 - 2}{6} = \frac{1}{6} \\ \\ \frac{ - 3}{4} \: divide \: by \: \frac{1}{6} \\ = \frac{ - 3}{4} \div \frac{1}{6} \\ = \frac{ - 3}{4} \times \frac{6}{1} \\ = \frac{ - 18}{4} = \frac{ - 9}{2}$

Answer 2

Hey mate
here is your answer............

$({x \div y})^{ - 1} = {x}^{ - 1} \div {y}^{ - 1} \\ = > ( \frac{7}{11} \div \frac{ - 22}{21} ) ^{ - 1} = { \frac{7}{11} }^{ - 1} \div { \frac{ - 22}{21} }^{ - 1} \\ = > ( \frac{7}{11} \times \frac{ - 21}{22} ) ^{ - 1} = \frac{11}{7} \div \frac{ - 21}{22} \\ = > (\frac{ - 147}{242} ) ^{ - 1} = \frac{11}{7} \times \frac{ - 22}{21} \\ = > \frac{ - 242}{147} = \frac{ - 242}{147}$