Question

plzz answer these questions..​

Answer 1

Step-by-step explanation:

$\sf Question 9\\ \\ \sf No\:of\:atoms\: present\:in 0.32\: g\: S{O}_{2} \\ \\ \sf Molecular\:wieght\:of\: S{O}_{2} = 32 + 16 × 2 = 64 g\:{mol}^{-1} \\ \\ \sf No. \:of \:moles = \frac{Given\:weight(W)}{Molecular\:weight(M)} \\ \\ \sf = \frac{0.32}{64} \\ \\ \sf = 0.5 × {10}^{-2} \\ \\ \sf No.\:of\:atoms = No.\:of\:moles\: × Avogadro's \: number \\ \\ \sf = 0.5 × {10}^{-2} × 6.022 × {10}^{ 23} \\ \\ \sf = 3.011 × {10}^{21} \\ \\ \bold {\sf No. \:of \: atoms\: in \: 0.32 g \: of \: S{O}_{2} \: is \: 3.011 × {10}^{21} }$

Answer 2

Answer:

Congratulations

Step-by-step explanation:

Congracts dear.

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from ur brainlyy frddd