Math, asked by ƒaiŗƴ, 9 months ago

plzz answer these questions...​

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Answered by sulsha3
2

Answer:

the question you have posted is wrong by the law of 0 dimentions it is incorrect see will explain how it is incorrect

Step-by-step explanation:  \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \leq \left \{ {{y=2} \atop {x=2}} \right. x^{2} \\ \\ \geq \int\limits^a_b {x} \, dxthis is the forlmula that should be used and you have used  ∛³²⇵β≥\sqrt{x} \sqrt[n]{x} \pi \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \leq \\ x^{2} \geq \neq  \lim_{n \to \infty} a_n \int\limits^a_b {x} \, dx  \lim_{n \to \infty} a_nunderstand

if you understood this then please mark me as brainliest thanks....

Answered by alov00722
5

Answer:

The electron configuration of an element describes how electrons are distributed in its atomic orbitals.

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