plzz answer this in note book
plz fast
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May this will help you
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Tiitu81:
konsa formula lagaya
colombs law ka
F=1/4πe• q1q2/r^2
okkk
it's a ncert question.... so the ans is in the ncert solution
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budy my net is slow so i give you solution withou notes okay
1 coulomb
q1=q2=q
let F= 9×10^9
r=1m
F= 9×10^9 q1q2/r^2.......(1)
9×10^9=9×10^9
q=+-(1)ans...
1 coulomb
q1=q2=q
let F= 9×10^9
r=1m
F= 9×10^9 q1q2/r^2.......(1)
9×10^9=9×10^9
q=+-(1)ans...
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