Question

plzz answer this plz

Answer 1

1)Let number of camels be N.

     N/4 + 2 √N + 15 = N
     3 N - 8 √N - 60 = 0
     √N = [ 8 +- √(64+720) ] /6 = 6 or -20/6
So N = 6² = 36
2)let x and y be the sides of the garden 
Area = 100 = xy (equation 1) 
30 = x + 2y (equation 2) 
From equation 2; x = 30-2y; substittute the value of x ineqn 1; 
Hence, 100 = (30-2y)y = 30y - 2y^2 
or 
y^2 - 15y + 50 = 0 
(y-10)(y-5) = 0
there are 2 possible values of y which ar 10 and 5, 
Hence there will be 2 possible values for x as well whch are: 
from equation 1: x = 100/y = 100/10 
x = 10 when y = 10 
x = 20 when y = 5
3)Total budget = no of students × amout brought by each student

let no. of students = x
and amount by each student = y
so ATQ
500= xy [y= 500/x]
but 5 students failed to come and 5rs were increades for everyone
so 500 = (x-5) (5y)
500 =5xy - 25y
putting value of y
500=(5x 500/x)- 25×500/x
500=2500 - 12500/x
500x = 10000
x = 20.....=>
xy=500
20y=500
y = 500/20
y = 25