Question

Plzz answer this question!!...

1+9a(2-7a)...this is the question of factorisation of class 8

If anyone knows plzz answer!!...​

Answer 1

Answer:

9a−2)⋅(a+1)

See steps

Step by Step Solution:

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STEP

1

:

Equation at the end of step 1

(32a2 + 7a) - 2

STEP

2

:

Trying to factor by splitting the middle term

2.1 Factoring 9a2+7a-2

The first term is, 9a2 its coefficient is 9 .

The middle term is, +7a its coefficient is 7 .

The last term, "the constant", is -2

Step-1 : Multiply the coefficient of the first term by the constant 9 • -2 = -18

Step-2 : Find two factors of -18 whose sum equals the coefficient of the middle term, which is 7 .

-18 + 1 = -17

-9 + 2 = -7

-6 + 3 = -3

-3 + 6 = 3

-2 + 9 = 7 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and 9

9a2 - 2a + 9a - 2

Step-4 : Add up the first 2 terms, pulling out like factors :

a • (9a-2)

Add up the last 2 terms, pulling out common factors :

1 • (9a-2)

Step-5 : Add up the four terms of step 4 :

(a+1) • (9a-2)

Which is the desired factorization

Final result :

(9a - 2) • (a + 1)

Explanation:

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