Question

Plzz answer this question.....​

Answer 1

Answer:

(3)

$10 ^{ - 4} m \: hcl \: and \: 10 ^{ - 5} m \: agno3$

Explanation:

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Answer 2

Ksp [ AgCl ] = 10 ^ -10

Ksp = [ Ag ^+ ] • [ Cl ^- ] / [ AgCL ]

As [ AgCL ] = 1, hence [Ag ^+ ] • [ Cl ^- ] = 10^-10

Note: If Ksp is less than the ionic product of the reaction then precipitate would be formed. Here, the excess reagent is AgCl {aq}

Hence option C is the correct option.

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