Question

Plzz answer this question

Answer 1

volume of water remaining in solid= volume of cone + volume of hemisphere-volume if cylinder

=

$1/3\pi rh{+2}/3\pi r{3} - \pi r^{2}h$

Answer 2

Answer:

Volume of water left in solid=volume of cone+volomr of hemisphere

Step-by-step explanation:

1/3+2/3-3