plzz answer this question
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Hey dude your ans is (y-1)(y^2+y-6)
Prabhjotkhepar132:
hlo
neha
Hi
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Given Equation is y^3 - 7y + 6
= > y^3 + y^2 - 6y - y^2 - y + 6
= > y(y^2 + y - 6) - 1(y^2 + y - 6)
= > (y - 1)(y^2 + y - 6)
= > (y - 1)(y^2 - 2y + 3y - 6)
= > (y - 1)((y(y - 2) + 3(y - 2))
= > (y - 1)(y - 2)(y + 3).
Hope this helps!
= > y^3 + y^2 - 6y - y^2 - y + 6
= > y(y^2 + y - 6) - 1(y^2 + y - 6)
= > (y - 1)(y^2 + y - 6)
= > (y - 1)(y^2 - 2y + 3y - 6)
= > (y - 1)((y(y - 2) + 3(y - 2))
= > (y - 1)(y - 2)(y + 3).
Hope this helps!
:-)
Thank you bro........Most Welcome!:-)
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