Question

plzz answer this question
give that log3x=r and log9y=s express xy^2 and x^2/y as power of 3
hence, giving that xy^2= 81 and x^2/y=1/3, determine the valuse of r and s

Answer 1

Please see the attachment

Answer 2

⇒f(x)+2f(1−x)=x^

2+2⋯⋯(i)

Put x=1−x

⇒f(1−x)+2f(x)

=(1−x)^2+2

Multiply by 2

⇒2f(1−x)+4f(x)=2(1−x)

2+4⋯⋯(ii)

Subtract (ii) from (i)

−3f(x)

=x^2−2−2(1−x) 2−3f(x)

=x^2−2−2x^2+4x−3f(x)

= −(x^2−4x+4)

f(x)=− 3(x−2)^2