Question

PLzz answer this question

URGENT☺️☺️☺️

Answer 1

Given

Z⁴+1/z⁴ =47

Adding and subtract 2


Z⁴+1/Z⁴ +2-2 =47


(z ²) ²+2(z ²) x1/z² +(1/x²) ² =47+2

(in above step I used (a+b)²=a²+2ab+b², where a=z², b=1/z²)

So now we can write


(z²+(1/z)²)²=49

(z²+(1/z)²)²=7²

Cancel ² both side, we get

Z²+1/z²=7

Z²+1/z²+2-2=7

Doing similar step what I did above

We get

(Z+1/z)²=7+2

(Z+1/z)²=9

(Z+1/z)²=3²

Z+1/z=3


Now

Z³+1/z³

=(z+1/z)³-3z x 1/z (z+1/z)

For above putting value of z+1/z=3

=3³-3x3

=27-9

=18

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Answer 2

Here is the answer hope it helps