Physics, asked by divyanshu8686, 10 months ago

PLZZ anwer it step by step ​

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Answers

Answered by MisterIncredible
3

Your answer:

Given :

Average speed in the first case = 20km h^-1

Average speed in the second case = 40 km h^-1

Required to find:

  1. Average speed in the whole trip

Solution:

In the question it is given that Abdul has 20 km/hr as average speed when going to the school .

similarly, while he was returning back he had an average speed of 40km/hr ( this is due to less traffic).

So , from this we can come to the idea that Abdul is going with a constant average speed . similarly while returning back his average speed was constant.

As , the average speed are constant through out the journey we can solve this question very simply using a formula

That is

s =  \frac{a + b}{2}

Here,

s represents average speed

a represents average speed in first case

b represents average speed in second case.

(depending upon our requirements we can increase the formula ).

so,

Calculations

s =  \frac{20 + 40}{2}  \\ s =  \frac{60}{2}  \\ s = 30

Hence ,

Average speed for Abdul trip is 30 km h^-1

Answered by abdulrubfaheemi
1

Answer:

Your answer:

Given :

Average speed in the first case = 20km h^-1

Average speed in the second case = 40 km h^-1

Required to find:

Average speed in the whole trip

Solution:

In the question it is given that Abdul has 20 km/hr as average speed when going to the school .

similarly, while he was returning back he had an average speed of 40km/hr ( this is due to less traffic).

So , from this we can come to the idea that Abdul is going with a constant average speed . similarly while returning back his average speed was constant.

As , the average speed are constant through out the journey we can solve this question very simply using a formula

That is

s = \frac{a + b}{2}s=

2

a+b

Here,

s represents average speed

a represents average speed in first case

b represents average speed in second case.

(depending upon our requirements we can increase the formula ).

so,

Calculations

\begin{gathered}s = \frac{20 + 40}{2} \\ s = \frac{60}{2} \\ s = 30\end{gathered}

s=

2

20+40

s=

2

60

s=30

Hence ,

Average speed for Abdul trip is 30 km h^-1

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