PLZZ anwer it step by step
Answers
Your answer:
Given :
Average speed in the first case = 20km h^-1
Average speed in the second case = 40 km h^-1
Required to find:
- Average speed in the whole trip
Solution:
In the question it is given that Abdul has 20 km/hr as average speed when going to the school .
similarly, while he was returning back he had an average speed of 40km/hr ( this is due to less traffic).
So , from this we can come to the idea that Abdul is going with a constant average speed . similarly while returning back his average speed was constant.
As , the average speed are constant through out the journey we can solve this question very simply using a formula
That is
Here,
s represents average speed
a represents average speed in first case
b represents average speed in second case.
(depending upon our requirements we can increase the formula ).
so,
Calculations
Hence ,
Average speed for Abdul trip is 30 km h^-1
Answer:
Your answer:
Given :
Average speed in the first case = 20km h^-1
Average speed in the second case = 40 km h^-1
Required to find:
Average speed in the whole trip
Solution:
In the question it is given that Abdul has 20 km/hr as average speed when going to the school .
similarly, while he was returning back he had an average speed of 40km/hr ( this is due to less traffic).
So , from this we can come to the idea that Abdul is going with a constant average speed . similarly while returning back his average speed was constant.
As , the average speed are constant through out the journey we can solve this question very simply using a formula
That is
s = \frac{a + b}{2}s=
2
a+b
Here,
s represents average speed
a represents average speed in first case
b represents average speed in second case.
(depending upon our requirements we can increase the formula ).
so,
Calculations
\begin{gathered}s = \frac{20 + 40}{2} \\ s = \frac{60}{2} \\ s = 30\end{gathered}
s=
2
20+40
s=
2
60
s=30
Hence ,
Average speed for Abdul trip is 30 km h^-1