Question

plzz do it fast......

Answer 1

Let the side of 1st square be 'a' and second square be 'b'
Areas = a^2 , b^2
Perimeters = 4a 4b
Given,
a^2 + b^2 = 468...(i)
4a-4b = 24
4(a-b) = 24
a-b = 6
a= b+6....(ii)
(ii) in (i)
(b+6)^2 + b^2 = 468
b^2 + 36 + 12b + b^2 = 468
2b^2 + 12b + 36-468 = 0
2b^2 + 12b - 432 = 0
b^2 + 6b - 216 = 0 
b^2 + 18b - 12b - 216 = 0
b(b+18) -12(b+18) = 0
(b-12)*(b+18) = 0
b=12
a= b+6 = 18
Hence sides of squares are 18 m, 12 m
Hope it helps.