Question

plzz explain...
I'll mark u the brainliest​

Answer 1

Step-by-step explanation:

0 < t < 1s : Velocity increases from 0 to 6 m/s

1 < t < 2s : Velocity increases from 6 to 0 m/s but car continues to move forward  

2 < t <3s : Since field strength is Same  

\therefore∴ Car's velocity increases from 0 to -6 m/s

Distance traveled in 1st second

S=\left(\dfrac{u+v}{2}\right)t=\left(\dfrac{0+6}{2}\right)(1)=3mS=(  

2

u+v

​  

)t=(  

2

0+6

​  

)(1)=3m

Distance=9m=9m  

So, Average speed =\dfrac{9m}{3s}=3\ m/s=  

3s

9m

​  

=3 m/s

Displacement =3m=3m

So, Average velocity =\dfrac{3m}{3s}=1\ m/s=  

3s

3m

​  

=1 m/s