Question

Plzz explain step by step solution of this..... I will mark brainliest.
12 coins are tossed 4096 times. The expected number of times that one can get atleast 2 heads is
1) 4080
2) 4081
3) 4082
4) 4083
​

Answer 1

If a coin is tossed 12 times, the maximum probability of getting heads is 12.

But, 12 coin tosses leads to

2

12

, i.e. 4096 number of possible sequences of heads & tails.

Let E be an event of getting heads in tossing the coin and S be the sample space of maximum possibilities of getting heads. Then probability of the event E can be defined as,

P

(

E

)

=

n

(

E

)

n

(

S

)

.

[Where, n represents number accordingly].

∴

P

(

E

)

=

495

4096

.

(answer)

Answer 2

Answer:

sorry I don't know so.

please make me as brilliant