Question

plzz factorise this questions fast​

Answer 1

${x}^{3} + \frac{1}{ {x}^{3} } - 2$

$x + \frac{1}{x} = y$

${x}^{3} + ( \frac{1}{x} ) {}^{3} + 3(x + \frac{1}{x} ) = { {y}^{3} }^{}$

${x}^{3} + ( \frac{1}{x} ) {}^{3 } + 3y = {y}^{3}$

given Expression becomes

$= {y}^{3} - 3y - 2$

$(y - 2)( {y}^{2} + 2y + 1)$

$(y - 2)(y + 1) {}^{2}$

$(x + \frac{1}{x} - 2)(x + \frac{1}{x} + 1) {}^{2}$

Answer 2

Answer:

x

3

+

x

3

1

−2

\begin{gathered}x + \frac{1}{x} = y \\ \end{gathered}

x+

x

1

=y

{x}^{3} + ( \frac{1}{x} ) {}^{3} + 3(x + \frac{1}{x} ) = { {y}^{3} }^{}x

3

+(

x

1

)

3

+3(x+

x

1

)=y

3

{x}^{3} + ( \frac{1}{x} ) {}^{3 } + 3y = {y}^{3}x

3

+(

x

1

)

3

+3y=y

3

given Expression becomes

= {y}^{3} - 3y - 2=y

3

−3y−2

(y - 2)( {y}^{2} + 2y + 1)(y−2)(y

2

+2y+1)

(y - 2)(y + 1) {}^{2}(y−2)(y+1)

2

(x + \frac{1}{x} - 2)(x + \frac{1}{x} + 1) {}^{2}(x+

x

1

−2)(x+

x

1

+1)

2