Question

plzz factorise this
${x}^{6} - 64$

Answer 1

Hola..!!

${x}^{6} - 64 \\ = {( {x}^{2} )}^{3} - {(4)}^{3} \\ = ( {x}^{2} - 4)( {( {x}^{2} )}^{2} + 4{x}^{2} + {(4)}^{2} ) \\ = ( {(x)}^{2} - {(2)}^{2} )( {x}^{4} + 4 {x}^{2} + 16) \\ = (x + 2)(x - 2)( {x}^{4} + 4 {x}^{2} + 16)$
Hope it'll help..