plzz find both question answer
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2.ar of triangleCAD=ar of triangle CDB
ar of triangle CDB=ar of triangle PDB + ar of triangle RDP +ar of triangle CRP
=a+b+c
CQ ll DP
ar triangle ADP = CDP
c+d = C+b
d=b
ar triangle CDB = a+ d + c
ar triangle CDB = BPQ.
ar CDB =1/2 ABC
BPQ = 1/2 ABC
ar of triangle CDB=ar of triangle PDB + ar of triangle RDP +ar of triangle CRP
=a+b+c
CQ ll DP
ar triangle ADP = CDP
c+d = C+b
d=b
ar triangle CDB = a+ d + c
ar triangle CDB = BPQ.
ar CDB =1/2 ABC
BPQ = 1/2 ABC
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