plzz find resultant resistance
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If the key is closed:
Effective Resistance = Parallel Combination1 + Parallel Combination2 + 7ohm
4*5/4+5= 20/9
3*6/3+6 = 18/9 = 2
2.23 + 7 + 2 = 11.23 ohms.
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Answer:
¹⁰¹/₉ Ω is the correct answer.
Explanation:
First finding the equivalent resistance in 1st Parallel Circuit.
⇒ R (eq.) = [R₁R₂] ÷ [R₁ + R₂]
= [4 × 5] ÷ [4 + 5]
= ²⁰/₉ Ω
Resistance in Series = 7 Ω
Finding the equivalent resistance in 2nd Parallel Circuit.
⇒ R (eq.) = [R₁R₂] ÷ [R₁ + R₂]
= [3 × 6] ÷ [3 + 6]
= 2 Ω
∴ Total Resistance = ²⁰/₉ Ω + 7 Ω + 2 Ω
= ²⁰/₉ Ω + ⁶³/₉ Ω + ¹⁸/₉ Ω
= ¹⁰¹/₉ Ω ←ANSWER
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