PLZZ frnds solve these qns
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nancypawansharmapami:
hii
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Answered by
5
Hey mate,
1) R = root (16 + 25 +2×4×5×root (3)/2)
= root (41 + 40×root (3)/2)
= root (82 + 40×root (3))/2
2) 5 = root (16 + 9 + 2×4×3×cosx)
Squaring both sides,
25 = 25 + 24×cosx
cosx = 0
x = 90°
3) 10 = root (16 + b^2 +2×4×b×1/root (2))
Squaring both sides,
100 = 16 + b^2 + 8b/root (2)
solve on your own!
4) Just refer to the 3) part to get the answer!
hope this helps you out!
1) R = root (16 + 25 +2×4×5×root (3)/2)
= root (41 + 40×root (3)/2)
= root (82 + 40×root (3))/2
2) 5 = root (16 + 9 + 2×4×3×cosx)
Squaring both sides,
25 = 25 + 24×cosx
cosx = 0
x = 90°
3) 10 = root (16 + b^2 +2×4×b×1/root (2))
Squaring both sides,
100 = 16 + b^2 + 8b/root (2)
solve on your own!
4) Just refer to the 3) part to get the answer!
hope this helps you out!
Answered by
0
hi sole the questions as ginen in pic.
But Data of Ur question is fully incorrect.
note:- i Q4 take b= 13
But Data of Ur question is fully incorrect.
note:- i Q4 take b= 13
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