plzz give a detailed solution for both
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1) APB =40
PAO=90
PBO=90......radius and tangent are perpendicular to each other
AOB=?
APB+PAO+PBO+AOB=360........... sum of all angles of traingle is 360
40+90+90+AOB=360
220+AOB=360
AOB =360-220
AOB= 140
2)AOB=125
COD=?
COD=AOB...........vertically opposite angles
COD=125
PAO=90
PBO=90......radius and tangent are perpendicular to each other
AOB=?
APB+PAO+PBO+AOB=360........... sum of all angles of traingle is 360
40+90+90+AOB=360
220+AOB=360
AOB =360-220
AOB= 140
2)AOB=125
COD=?
COD=AOB...........vertically opposite angles
COD=125
amitpatidar4364:
sorry but ur both answers are wrong !! 1st is 70° and 2nd is 55°
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