Question

plzz give correct answer​

Answer 1

Answer:

what is the question mmmmmmmm

Answer 2

you can see the figure of the question above

so I am giving you only solution

Let AB be the height of building and CD be the height of tower

Draw BE perpendicular to CD.letCD=h metre

then,CE=AB=7m and DE=(h-7)m

from right∆CAB,we have

AC/AB=cot45°

AC/7m=1

AC=7m

.. BE=AC=7m

from∆BED,we have

DE/BE=tan60°

h-7/7=√3

h=7√3+7=7(√3+1)= 7(1.732+1)

h=7×2.732=19.12m