Question

plzz guys help me tomorrow is my exam
pl solve this easy que

Answer 1

$\frac{2(2x - 1)}{(x + 3)} - \frac{3(x + 3)}{(2x - 1)} = 5 \\ \\ \therefore \: \frac{4x - 2}{x + 3} - \frac{3x + 9}{2x - 1} = 5 \\ \\ \therefore \: \frac{(4x - 2)(2x - 1) - (3x + 9)(x + 3)}{(x + 3)(2x - 1)} = 5 \\ \\ \therefore \: \frac{(8 {x}^{2} - 4x - 4x + 2 ) - (3 {x}^{2} + 9x + 9x + 27) }{2 {x}^{2} - x + 6x - 3} = 5 \\ \\ \therefore \: \frac{8 {x}^{2} - 3 {x}^{2} - 8x - 18x + 2 - 27 }{2 {x}^{2} + 5x - 3} = 5 \\ \\ \therefore \: \frac{5 {x}^{2} - 26x - 25}{2 {x}^{2} + 5x - 3} = 5 \\ \\ \therefore \: 5 {x}^{2}-26x-25=10 {x}^{2}+25x-15 \\ \\ \therefore \: 5 {x}^{2} + 51x + 10 = 0$