plzz guys solve this some coudn't solve it i need your help plzz help
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A,B,C are interior angles of triangle ABC
- Sin[ B+C/2] = CosA/2
- A+B+C = 180°
- B+C= 180- A
- B+C = 90- A/2
Sin( B+C/2) = Sin( 90-A/2)
Sin(B+C/2) = Cos A/2
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