Question

PLZZ help!! maths lines and amgles ​

Answer 1

Step-by-step explanation:

Given that

AB//CD and LGED=126°

EF is perpendicular to CD

LFED=90°

=>LGED=LGEF+LFED

=>126°=LGEF+90°

=>LGEF=126-90

=>LGEF=36°

And LEFG=90°

in ∆FGE,Sum of all angles is 180°

=>LFGE+LGEF+LEFG=180°

=> LFGE+36°+90°=180°

=>LFGE=180°-126°

=>LFGE=54°

LFGE+LAGE=180°(Linear pair)

=>54°+LAGE=180°

=>LAGE=180°-54°

=>LAGE=126°