Question

plzz help me by solving this

Answer 1

HELLO DEAR,

LENTH OF THE TRIANGLE= LM=10CM
AMD THE HEIGHT OC =10CM


NOW THE AREA OF THE SILVER PAINTING


= > AREA OF ∆OML - AREA OF SECTOR
(OKN)


$\frac{1}{2} \times 10 \times 10 - \frac{theta}{360} \pi {r}^{2} \\ = > 50 - \frac{90}{360} \times \frac{22}{7} \times {7}^{2} \\ = > 50 - \frac{1}{4} \times 22 \times 7 \\ = > 50 - \frac{77}{2} \\ = > \frac{(100 - 77)}{2} \\ = > \frac{23}{2} c {m}^{2}$


AND THE COST

=>
$= > 25 \times \frac{23}{2} \\ = > \frac{575}{2} = 287.5rupees$
I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

yes.......................