Chemistry, asked by Nani11111111, 1 year ago

plzz help me frnds
who will answer correctly they will be marked as brainliest..

Attachments:

Answers

Answered by ChetanRA
0
As this is a competitive exam question, let us solve it with minimum working.

Half life is the amount of time required for a substance to decay to one-half of its original weight. Thus, if 1g of a substance undergoes disintegration equivalent to 1 half life, 0.5 g will disintegrate and 0.5 g will remain.

We see that both the nuclides disintegrate for 4 minutes. The half-life of A is 1 minute, hence it undergoes disintegration equivalent to 4 half lives.
In one half life,  \frac{1}{2} of the substance remains. So, after 4 half lives, ( \frac{1}{2} ) ^{4} will remain, i.e.  \frac{1}{16} will remain. Hence, we can say 1 -  \frac{1}{16}   =  \frac{15}{16} of the element has disintegrated.

Coming to nuclide B, it has a half-life of 2 minutes. Thus, it undergoes a disintegration equivalent to 2 half lives. In 2 half lives, ( \frac{1}{2}  ) ^{2}  \frac{1}{4} of the element will remain. Thus, 1 -   \frac{1}{4}   =   \frac{3}{4}  would have disintegrated.

Taking the ratio of the weights of A and B disintegrated, we have
 \frac{15}{16} :  \frac{3}{4}
Canceling the denominators and numerators, we have
 \frac{5}{4} :  \frac{1}{1}
Multiplying each side by 4, we have
 \frac{5}{4} * 4 :   \frac{1}{1} * 4
= 5 : 4

Thus, option (2), i.e., 5:4 is the correct answer.

Nani11111111: Tq so much friend
Answered by Dsn
0
As this is a competitive exam question, let us solve it with minimum working.

Half life is the amount of time required for a substance to decay to one-half of its original weight. Thus, if 1g of a substance undergoes disintegration equivalent to 1 half life, 0.5 g will disintegrate and 0.5 g will remain.

We see that both the nuclides disintegrate for 4 minutes. The half-life of A is 1 minute, hence it undergoes disintegration equivalent to 4 half lives.
In one half life, of the substance remains. So, after 4 half lives, will remain, i.e.  will remain. Hence, we can say 1 -   = of the element has disintegrated.

Coming to nuclide B, it has a half-life of 2 minutes. Thus, it undergoes a disintegration equivalent to 2 half lives. In 2 half lives,  =  of the element will remain. Thus, 1 -    =   would have disintegrated.

Taking the ratio of the weights of A and B disintegrated, we have
:
Canceling the denominators and numerators, we have
:
Multiplying each side by 4, we have
* 4 :   * 4
= 5 : 4

Thus, option (2), i.e., 5:4 is the correct answer.

Thanks
Mark me as the brainliest
Similar questions