plzz help me on solving such stupid question .Its my kind request to u
Answers
Answer:
answer B
Step-by-step explanation:
Let L = 10
Let W = 10 (a square is a rectangle)
Original area = (LW) = 10*10 = 100
L increases by 20 percent:
(1.2)(10) = 12
W decreases by 20 percent:
(0.8)(10) = 8
New area: (12)*(8) = 96
Percent change:New−OldOld∗100New−OldOld∗100
96−100100=96−100100=
(−.04)∗100(−.04)∗100 = 4 percent decrease
Algebra
L = length
W = width
Area = (1)LW
Length increases by 20 percent, width decreases by 20 percent:
1.2L * 0.8W = (.96) LW
.96 is 4 percent less than 1
The area decreases by 4 percent
Answer:
4% decrease, option B
Step-by-step explanation:
Let length be L and width be W
Original area of rectangle = length × width = L × W = LW
New length = length + 20% of length
= L + [(20/100) × L]
= 1.2 × L = 1.2L
New width = width - 20% of width
= W - [(20/100) × W]
= 0.8W
New area = 1.2L × 0.8W = 0.96LW
% change in area = [(0.96LW - LW)/LW] × 100
= -0.04 × 100 = -4
As the % change is negetive, So area of rectangle will have 4% decrease.