Question

Plzz help me with this question​

Answer 1

Answer:

Hope it helps u.....

in this figure this parallogram ABED.which meet at point c.

proof =>in ∆ACD andECB

AC=DC (given)

CB=CE (given)

<ACD=ECB (vertically opposite angle)

so ∆ACD~=∆ECD by SAS congruent

AB=DE by (cpct)

and I think axiom 5

Answer 2

I hope you understood this