plzz help Mee... Tomarrow is my exam... plzz.. answer... me...
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Answered by
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mid point of A(0,-1) B(2,1) is 0+2)/2,-1+1)/2 = 1,0
mid point of B(2,1) C(0,3) is 2+0)/2,1+3)/2 = 1,2
mid point of C(0,3) A(0,-1) is 0,1
So G=(1,0) F(1,2) E(0,1)
GF = √0 +4 = 2
FE = √1+1 =√2
GE = √1+1 =√2
semi perimeter = 2+2√2)/2 = 1+√2
area = √s(S-GF)(S-FE)(S-GE)
=√(1+√2)(-1+√2)
√2-1 =1
mid point of B(2,1) C(0,3) is 2+0)/2,1+3)/2 = 1,2
mid point of C(0,3) A(0,-1) is 0,1
So G=(1,0) F(1,2) E(0,1)
GF = √0 +4 = 2
FE = √1+1 =√2
GE = √1+1 =√2
semi perimeter = 2+2√2)/2 = 1+√2
area = √s(S-GF)(S-FE)(S-GE)
=√(1+√2)(-1+√2)
√2-1 =1
Answered by
1
bro i think this photo will help you solve the question.......all the best for your exam....
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ckarthikraj200209:
no boy...
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