Question

There are two bags of rice. One bag weighs 461/6kg and other weighs 128/3kg. If 5/7 of the total weight is sold, find the weight of the remaining rice.

Answer 1

416/6 + 128/3= 717/6
Let,
7-5/7= 2/7
So,
2/7 of 717/6 = 239/7
So, your answer is 239/7.

Answer 2

Answer:

Amount of rice left in the bag = 239/7 Kg

Step-by-step explanation:

Weight of the first bag = 461/6 Kg

Weight of the second bag = 128/3 Kg

$\implies \text{Total weight = }\frac{461}{6}+\frac{128}{3}\\\\\implies \text{Total weight = }\frac{461+128\times 2}{6}\\\\\implies \text{Total weight = }\frac{717}{6}$

Given that the 5/7 of the total weight, the rice has been sold

⇒ Amount of rice sold = 5/7 × 717/6

                                     = 1195/14

So, Amount of rice left in the bag = 239/2 - 1195/14

                                                        = 239/7 Kg