Question

Plzz no unesecesary answers...

Find The Lettered Angles In The Figure..​

Answer 1

Answer:

X =30' y =50

Step-by-step explanation:

in ∆ABD,

using angle sum property of a triangle,

angleA + angleB+ angle D = x + 60° + 90° = 180°

so, X = 180°- 90°- 60°

X = 30°

in ∆ACD

using angle sum property of a triangle,

Angle A + angle C + angle D = 40°+ y+ 90° = 180°

so, y = 180° - 90° - 40°

y= 50°

Answer 2

Answer:

x = 30°. y = 50°.

Step-by-step explanation:

∆ADB is right angled triangle

therefore,

angle A + angle D + angle B = 180°

x + 90° + 60° = 180°

x + 150° = 180°

x = 180° - 150°

x = 30°

∆ADC is right angled triangle

therefore,

angle A + angle D + angle C = 180°

40° + 90° + y = 180°

130° + y = 180°

y = 180° - 130°

y = 50°