Question

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Answer 1

Answer:

20√3 (or ) 34.64 m

Step-by-step explanation:

Length of the tower be AB = x.

Length of the shadow when the sun's altitude is 60° be BC = h

Length of the shadow when the angle of elevation is 30° be DB.

Now,

Given that shadow of tower is 40 m longer when sun's altitude is 30°.

∴ DB = (40 + x)

(i) In ΔABC:

tan 60° = AB/BC

√3 = h/x

h = √3x

(ii) In ΔABD:

tan 30° = AB/BD

⇒ (1/√3) = h/(x + 40)

⇒ (1/√3) = (√3x)/(x + 40)

⇒ x + 40 = 3x

⇒ 2x = 40

⇒ x = 20.

Substitute x = 20 in (i), we get

⇒ h = √3x

⇒ h = 20√3

⇒ h = 20 * (1.732)

⇒ h = 34.64 m

Therefore, the height of the tower is 20√3 m (or) 34.64 m.

Hope it helps!

Answer 2

Answer:

refers to the attachment