Question

plzz slove 2 & 3 .....

Answer 1

2)tan theta = Perpendicular/Base, =3/4

Hypotenuse=√(3)^2+(4)^2, =√9+16,= √25, 5

Therefore,

cos thetha=Base/hypotenuse ,=4/5

sec thetha=Hypotenuse/Base, =5/4

3)cot thetha=Base/Perpendicular, =40/9

Hypotenuse=√(40)^2+(9)^2, =√1600+81,= √1681, =41

Therefore,

sin thetha=Perpendicular/hypotenuse, =9/41

cosec thetha =hypotenuse/perpendicular,=41/9

Answer 2

Here is ur answer..

I hope it help you..

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