Question

Plzz solve 10th and 11th fast..........

Give correct answer.....

Answer 1

A 11. Present age = 3(x-4) = (x+12)
3x - 12 = x + 12
3x - x = 12 + 12
2x = 24
x = 12

Therefore, present age is 12 years.

Answer 2

11.

Let the present age be 'x'.
Age 12 years hence = (x+12)
Age 4 years ago = (x-4)

A/Q,
 x+12 = 3 (x-4)
x + 12 = 3x -12
2x = 24
x =12.
∴Present age = 12 years.


12.
Given, 3x-1 and 2x+2 are equal sides of isoceles Δ.
∴ 3x -1 = 2x +2
    x = 3 units

∴2x = 3.2 = 6 units

Perimeter = 3x-1 + 2x +2 + 2x
                 = 8+ 8+6
                 = 22 units.
10.

Let the no of 10 rupees notes be 'x'
So, total money as 10 rupees notes = 10x.

Given, no of 50 rupees notes is 1 less than then no of rupees 10 notes.
Total money as 50 rupees notes = 50 (x-1)= 50x -50

A/Q,
10x + 50x - 50 = 550
60x = 600
x= 10.

So, no of 10 rupees notes = 10.
No. of 50 rupees notes = 9

Hope it helped!
NISHTHA