plzz solve anyone .....
Attachments:
Answers
Answered by
0
Hi Mate!!!
Req = 8kOhm
By ohm's law
V = I R
I = 72 / 8
I = 9mA
Now Current through 4kohm and in 2Kohm will be same because they are in series.
Let current in 6Kohm be i'
i' =( 3 / 9 )9
i' = 3MA
Hope it helps..
Req = 8kOhm
By ohm's law
V = I R
I = 72 / 8
I = 9mA
Now Current through 4kohm and in 2Kohm will be same because they are in series.
Let current in 6Kohm be i'
i' =( 3 / 9 )9
i' = 3MA
Hope it helps..
Answered by
0
heya!!!
here is ua answer:
here is ua answer:
Attachments:
Similar questions