plzz solve from LHS....
Attachments:
Answers
Answered by
2
(secA - tanA )² = LHS
=> ( (1/cosA) - (sinA/tanA) )²
=> (1+sin²A-2sinA) / cos²A --------------1
(1 - sinA) / (1 + sinA) = RHS
=> rationalize it u get:
=> (1-sinA)² / (1 - sinA)(1+sinA)
=> (1+sin²A-2sinA) / 1 - sin²A
=> (1+sin²A-2sinA) / cos²A -------------- 2
hence 1 = 2
hence proved
hope it helped and wish u give me brainliest =)
=> ( (1/cosA) - (sinA/tanA) )²
=> (1+sin²A-2sinA) / cos²A --------------1
(1 - sinA) / (1 + sinA) = RHS
=> rationalize it u get:
=> (1-sinA)² / (1 - sinA)(1+sinA)
=> (1+sin²A-2sinA) / 1 - sin²A
=> (1+sin²A-2sinA) / cos²A -------------- 2
hence 1 = 2
hence proved
hope it helped and wish u give me brainliest =)
Similar questions