plzz solve it
............
Attachments:
Answers
Answered by
0
HELLO
Which Institute did u joined....
ANSWER ⤵⤵⤵
limx--0=sin^-1 (sec x)
Cos 0 = 1 =>Sec 0= Infinity
=sin^-1(infinity )
= Undefined
As range of Sin x is -1 to 1
☺☺☺
Tnxx
Which Institute did u joined....
ANSWER ⤵⤵⤵
limx--0=sin^-1 (sec x)
Cos 0 = 1 =>Sec 0= Infinity
=sin^-1(infinity )
= Undefined
As range of Sin x is -1 to 1
☺☺☺
Tnxx
shobhit66:
but rgt ans is 4th, in asked jee mains.
how?
right option D
Answered by
0
Your answer is given below:
limx--0=sin^-1 (sec x)
=sin^-1(1)
= \frac{\pi}{2}=
2
π
Similar questions