Question

plzz solve it
............​

Answer 1

HELLO

Which Institute did u joined....

ANSWER ⤵⤵⤵

limx--0=sin^-1 (sec x)
Cos 0 = 1 =>Sec 0= Infinity
=sin^-1(infinity )

= Undefined

As range of Sin x is -1 to 1

☺☺☺

Tnxx

Answer 2

Your answer is given below:

limx--0=sin^-1 (sec x)

=sin^-1(1)

= \frac{\pi}{2}=

2

π