Question

Plzz solve it.
I want full solution.

Answer 1

we know that

(a+b+c)²= a²+b²+c²+ 2(ab+bc+ac)

Given........
a+b+c= 8.........(1)
ab+bc+ac= 19........(2)

8²= a²+b²+c²+2(19)
64-38= a²+ b²+ c²
a²+b²+c²= 26
Hope this helps you...✌

Answer 2

(a+b+c) =8

(ab+bc+ca)=19


$(a + b + c) {}^{2} =a {}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca \\( 8 {)}^{2} = (a {}^{2} + {b}^{2} + {c}^{2}) + 2ab + 2bc + 2ca \\ 64 = (a {}^{2} + {b}^{2} + {c}^{2}) + 2(ab + bc + ca) \\ 64 = (a {}^{2} + {b}^{2} + {c}^{2}) + 2(19) \\ 64 = (a {}^{2} + {b}^{2} + {c}^{2}) + 38 \\ 64 - 38 = (a {}^{2} + {b}^{2} + {c}^{2}) \\ 26 = (a {}^{2} + {b}^{2} + {c}^{2})$