Plzz solve it with explanation....
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Answer:
sin^-1[(√7+3√8)/12]
Step-by-step explanation:
we have,
sin^-1(1/3)+sin^-1(3/4)
as we know,
sin^-1(x)+sin^-1(y) = sin^-1[x√(1-y²)+
y√(1-x²)]
so, in above question:
sin^-1[1/3√(1-9/16)+3/4√(1-1/9)]
= sin^-1[1/3×√7/4+3/4×√8/3]
= sin^-1[(√7+3√8)/12] ...ans.
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