Math, asked by hrik2, 1 year ago

plzz solve Q 11 in the following image

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Answers

Answered by FadhilPrawira
4
Q 11
exampleSujata = xSushma = y
the first equation \frac{x}{y}\ =\ \frac{4}{3} x =  \frac{4}{3}\ -\ y x-8 =  \frac{4}{3}\ -\ (y-8) 3(x-8) = 4(y-8)3x-24 = 4y-323x-4y = -8
the second equation \frac{x}{y}\ =\ \frac{7}{6} x =  \frac{7}{6}\ -\ y x+9 =  \frac{7}{6}\ -\ (y+9) 6(x+9) = 7(y+9)6x+54 = 7y+636x-7y = 9
answer
method of elimination
3x-4y = -8|·2| 6x-8y = -166x-7y = 9|·1| 6x-7y = 9
6x-8y = -166x-7y = 9--------------   ------x = -25x = 25
3x-4y = -83.25 - 4y = -875 - 4y = -8-4y = -834y = 83y = 20,75

FadhilPrawira: sorry its Q 10, i will correct it
hrik2: okkk...
hrik2: no problem... plzzz corect it..
FadhilPrawira: thanks for best answer :)
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