plzz solve Q 18 in the following image
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pudiprashanth:
which class and which exercise?
clas 8 ex 38 b
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∵, AX bisects BC; X is the mid point of BC.
∴, BC=2BX -------------------------(1)
Again, AX bisects ∠A.
∴, ∠XAB=∠DAX -------------------(2)
Now, since AD||BC
∴, ∠AXB=∠DAX (Alternate angles)
∴, ∠AXB=∠XAB [using (2)]
∴, AB=BX
∴, BC=2AB [using(1)]
or, AD=2AB [∵, ABCD is a parallelogram]
(Proved)
∴, BC=2BX -------------------------(1)
Again, AX bisects ∠A.
∴, ∠XAB=∠DAX -------------------(2)
Now, since AD||BC
∴, ∠AXB=∠DAX (Alternate angles)
∴, ∠AXB=∠XAB [using (2)]
∴, AB=BX
∴, BC=2AB [using(1)]
or, AD=2AB [∵, ABCD is a parallelogram]
(Proved)
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