Question

plzz solve Q i ii ii iv v vi in the following image

Answer 1

1) Zn +2NaOH ------>  Na₂ZnO₂ + H₂
2)2Na +2H2O ------> 2NaOH + H₂
3)2CuO --------> 2Cu + O₂
4)2ZnS+3O₂ -------> 2ZnO + 2SO₂
5)FeSO₄ + 2 NaOH =Fe(OH)₂ + Na₂SO₄
6)3Fe+4H₂O ------->  Fe₃O₄+ 4H₂ or 3Fe + 2O₂ ------> Fe3O4

Hope it is clear now :)

Answer 2

Answer:

Explanation:

Converting All we get :-

1. Zn +2NaOH →  Na₂ZnO₂ + H₂
2. 2Na +2H2O → 2NaOH + H₂
3. 2CuO → 2Cu + O₂
4. 2ZnS+3O₂ → 2ZnO + 2SO₂
5. FeSO₄ + 2 NaOH = Fe(OH)₂ + Na₂SO₄
6. 3Fe+4H₂O →  Fe₃O₄+ 4H₂ or 3Fe + 2O₂ → Fe3O4