plzz solve question 9 and 13
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9.
Let the height of the rectangular park = 4x.
Let the breadth of the rectangular park = 3x.
Given that Area of the rectangular park = 2352m^2.
We Know that Area of the rectangle = l * b
2352 = 4x * 3x
2352 = 12x^2
2352/12 = x^2
196 = x^2
x = 14m.
Therefore the length = 4 * 14 = 56m.
the breadth = 3 * 14 = 42m.
We know that perimeter of the field = 2(l + b)
= 2(56 + 42)
= 2(98)
= 196.
Given that cost of fencing per metre = 10.50.
Therefore the cost of fencing = 10.50 * 196
= 2058 rupees.
13.
Let the altitude of the triangular field = x.
Then the base of the triangular field = 3x.
Given that cost of cultivating the field at the rate of 15 rupees per m^2 = 2250.
= 2250/15
= 150.
We know that Area of the triangle = 1/2 * b * h
150 = 1/2 * 3x * x
150 = 3x^2/2.
3x^2 = 300
x^2 = 300/3
x^2 = 100
x = 10.
Therefore the altitude of the field = 10m.
the base of the field = 3 * 10
= 30m.
Hope this helps!
Let the height of the rectangular park = 4x.
Let the breadth of the rectangular park = 3x.
Given that Area of the rectangular park = 2352m^2.
We Know that Area of the rectangle = l * b
2352 = 4x * 3x
2352 = 12x^2
2352/12 = x^2
196 = x^2
x = 14m.
Therefore the length = 4 * 14 = 56m.
the breadth = 3 * 14 = 42m.
We know that perimeter of the field = 2(l + b)
= 2(56 + 42)
= 2(98)
= 196.
Given that cost of fencing per metre = 10.50.
Therefore the cost of fencing = 10.50 * 196
= 2058 rupees.
13.
Let the altitude of the triangular field = x.
Then the base of the triangular field = 3x.
Given that cost of cultivating the field at the rate of 15 rupees per m^2 = 2250.
= 2250/15
= 150.
We know that Area of the triangle = 1/2 * b * h
150 = 1/2 * 3x * x
150 = 3x^2/2.
3x^2 = 300
x^2 = 300/3
x^2 = 100
x = 10.
Therefore the altitude of the field = 10m.
the base of the field = 3 * 10
= 30m.
Hope this helps!
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