Math, asked by ssimran, 1 year ago

plzz solve question 9 and 13

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Answered by vanshita6
1
hope you understand the solution to
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ssimran: thanks
Answered by siddhartharao77
1
9.

Let the height of the rectangular park = 4x.

Let the breadth of the rectangular park = 3x.

Given that Area of the rectangular park = 2352m^2.

We Know that Area of the rectangle = l * b

                           2352 = 4x * 3x

                           2352 = 12x^2

                           2352/12 = x^2

                           196 = x^2

                           x = 14m.


Therefore the length = 4 * 14 = 56m.

               the breadth = 3 * 14 = 42m.


We know that perimeter of the field = 2(l + b)

                                                             = 2(56 + 42)

                                                             = 2(98)

                                                             = 196.


Given that cost of fencing per metre = 10.50.


Therefore the cost of fencing = 10.50 * 196

                                                  = 2058 rupees.




13.

Let the altitude of the triangular field = x.

Then the base of the triangular field =  3x.

Given that cost of cultivating the field at the rate of 15 rupees per m^2 = 2250.

 = 2250/15

= 150.

We know that Area of the triangle = 1/2 * b * h

                                150                     = 1/2 * 3x * x

                                 150                     = 3x^2/2.

                                 3x^2 = 300

                                   x^2 = 300/3

                                  x^2 = 100

                                    x = 10.


Therefore the altitude of the field = 10m.

                 the base of the field = 3 * 10

                                                    = 30m.



Hope this helps!

siddhartharao77: Thank You ssimran for the brainliest
ssimran: thank u to
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