plzz solve question no.16 and 17
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16) according to Rault's law ,
we know,
PA =XA.PA°
=0.4×100= 40 mm
P = XA.P°A + (1 - XA)PB°
=0.4×100 +(1-0.4)×200
=40 + 120 = 160 mm
mole fraction of A in vapour phase
= PA/P = 40/160 = 1/4 =0.25
option (3) is correct .
17) vapour pressure of benzene(PA) = 160mm
vapour pressure of Toluene (PB) =60mm
we know,
P = PA + PB
=160 + 60 = 220 mm
now, mole fraction of toluene = PB/P
=60/220 = 6/22 = 3/11 = 0.28 ≈0.27
so, option (3) is correct
we know,
PA =XA.PA°
=0.4×100= 40 mm
P = XA.P°A + (1 - XA)PB°
=0.4×100 +(1-0.4)×200
=40 + 120 = 160 mm
mole fraction of A in vapour phase
= PA/P = 40/160 = 1/4 =0.25
option (3) is correct .
17) vapour pressure of benzene(PA) = 160mm
vapour pressure of Toluene (PB) =60mm
we know,
P = PA + PB
=160 + 60 = 220 mm
now, mole fraction of toluene = PB/P
=60/220 = 6/22 = 3/11 = 0.28 ≈0.27
so, option (3) is correct
abhi178:
means i take more time to solve this . for this question only 2-3 minutes required
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