Question

plzz solve the 15th question i need it very urgent​

Answer 1

Answer:

-1/2

Step-by-step explanation:

$\frac{x}{10} + \frac{y}{5} - 1 = 0 \: \: \: \: \: \: \: - > x + 2y = 10 \: \: \: .......(i) \\ \frac{x}{8} + \frac{y}{6} = 15 \: \: \: \: - > 3x + 4y = 360 \: ..........(ii) \\ multiply \: eq \: (i) \: by \: 2 \: and \: subtract \: from \: \: (ii) \\ 3x + 4y = 360 \: \: \: \: \: (ii) \\ 2x + 4y = 20 \: \: ....(i) \\ - \: - \: \: \: \: \: \: \: - \\ { ---------- } \\ x + 0 = 340 \\ x = 340 \\ put \: in \: eq \: (1) \\ 340 + 2y = 10 \\ y = \frac{10 - 340}{2} \\ y = -165 \\ \\ \\ now \: (3) \: eqution \: is \: \\ y = \alpha x + 5 \\ put \: values \: of \: x \: and \: y \\ we \: get \\ - 165 = \alpha (340) + 5 \\ \alpha = \frac{ - 165 - 5}{340} \\ \frac{ - 170}{340} = \frac{ - 1}{2} \\ hence \: \alpha = \frac{ - 1}{2}$

I use alpha instead of lambda.....

Hope it helps you.....