plzz solve the problem if u can.
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mole = volume at STP /22.4 L
moles of carbon = 1000g/12
volume of air needed at STP = 1000/12×22.4L
= 1866.67L
moles of carbon = 1000g/12
volume of air needed at STP = 1000/12×22.4L
= 1866.67L
anitagorai:
given ans. is 1st option
what
yes
but I did correct as volume of C at STP = volume of air needed for combustion
i did the same but ans is not matching
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