plzz solve the question with solution
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Answered by
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Given: p=99
putting the value of p in this equation
p(p²+3p+3)
so, 99(99²+3×99+3)
99(9801+297+3)
99(10101)
999999
I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST
putting the value of p in this equation
p(p²+3p+3)
so, 99(99²+3×99+3)
99(9801+297+3)
99(10101)
999999
I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST
Answered by
1
p = 99
99 ( 99^2 + 3 ( 99 ) + 3 )
= 99 ( 9801 + 297 + 3 )
= 99 ( 9801 + 300 )
= 999 ( 10101 )
= 99999
So the correct option is 4) 99999
Hope it helps you .
99 ( 99^2 + 3 ( 99 ) + 3 )
= 99 ( 9801 + 297 + 3 )
= 99 ( 9801 + 300 )
= 999 ( 10101 )
= 99999
So the correct option is 4) 99999
Hope it helps you .
udit43:
Most welcome
Thanks a lot for marking my answer brainliest.
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